Base | Representation |
---|---|
bin | 111010011001001101… |
… | …1001111101010101001 |
3 | 102222200100022210120210 |
4 | 1310302123033222221 |
5 | 4023304403220231 |
6 | 133335154211333 |
7 | 12026346606234 |
oct | 1646233175251 |
9 | 388610283523 |
10 | 125400054441 |
11 | 49200074a32 |
12 | 20378283b49 |
13 | ba95ba625c |
14 | 60d85c441b |
15 | 33de0d1a46 |
hex | 1d326cfaa9 |
125400054441 has 4 divisors (see below), whose sum is σ = 167200072592. Its totient is φ = 83600036292.
The previous prime is 125400054427. The next prime is 125400054443. The reversal of 125400054441 is 144450004521.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 125400054441 - 213 = 125400046249 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 125400054399 and 125400054408.
It is not an unprimeable number, because it can be changed into a prime (125400054443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20900009071 + ... + 20900009076.
It is an arithmetic number, because the mean of its divisors is an integer number (41800018148).
Almost surely, 2125400054441 is an apocalyptic number.
It is an amenable number.
125400054441 is a deficient number, since it is larger than the sum of its proper divisors (41800018151).
125400054441 is an equidigital number, since it uses as much as digits as its factorization.
125400054441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41800018150.
The product of its (nonzero) digits is 12800, while the sum is 30.
Adding to 125400054441 its reverse (144450004521), we get a palindrome (269850058962).
The spelling of 125400054441 in words is "one hundred twenty-five billion, four hundred million, fifty-four thousand, four hundred forty-one".
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