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125400054441 = 341800018147
BaseRepresentation
bin111010011001001101…
…1001111101010101001
3102222200100022210120210
41310302123033222221
54023304403220231
6133335154211333
712026346606234
oct1646233175251
9388610283523
10125400054441
1149200074a32
1220378283b49
13ba95ba625c
1460d85c441b
1533de0d1a46
hex1d326cfaa9

125400054441 has 4 divisors (see below), whose sum is σ = 167200072592. Its totient is φ = 83600036292.

The previous prime is 125400054427. The next prime is 125400054443. The reversal of 125400054441 is 144450004521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 125400054441 - 213 = 125400046249 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 125400054399 and 125400054408.

It is not an unprimeable number, because it can be changed into a prime (125400054443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20900009071 + ... + 20900009076.

It is an arithmetic number, because the mean of its divisors is an integer number (41800018148).

Almost surely, 2125400054441 is an apocalyptic number.

It is an amenable number.

125400054441 is a deficient number, since it is larger than the sum of its proper divisors (41800018151).

125400054441 is an equidigital number, since it uses as much as digits as its factorization.

125400054441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41800018150.

The product of its (nonzero) digits is 12800, while the sum is 30.

Adding to 125400054441 its reverse (144450004521), we get a palindrome (269850058962).

The spelling of 125400054441 in words is "one hundred twenty-five billion, four hundred million, fifty-four thousand, four hundred forty-one".

Divisors: 1 3 41800018147 125400054441