12540343 has 4 divisors (see below), whose sum is σ = 12547440. Its totient is φ = 12533248.

The previous prime is 12540331. The next prime is 12540347. The reversal of 12540343 is 34304521.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 12540343 - 2¹³ = 12532151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12540347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1446 + ... + 5212.

It is an arithmetic number, because the mean of its divisors is an integer number (3136860).

Almost surely, 2^12540343 is an apocalyptic number.

12540343 is a deficient number, since it is larger than the sum of its proper divisors (7097).

12540343 is an equidigital number, since it uses as much as digits as its factorization.

12540343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7096.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 12540343 is about 3541.2346716929. The cubic root of 12540343 is about 232.3288477162.

Adding to 12540343 its reverse (34304521), we get a palindrome (46844864).

The spelling of 12540343 in words is "twelve million, five hundred forty thousand, three hundred forty-three".