Base | Representation |
---|---|
bin | 10111010110111100… |
… | …10100100100010010 |
3 | 1012100222012212121212 |
4 | 23223132110210102 |
5 | 201140333411124 |
6 | 5432215020122 |
7 | 622523510534 |
oct | 135336244422 |
9 | 35328185555 |
10 | 12540528914 |
11 | 535588aa91 |
12 | 251b96a642 |
13 | 124b13a114 |
14 | 86d723854 |
15 | 4d5e4240e |
hex | 2eb794912 |
12540528914 has 4 divisors (see below), whose sum is σ = 18810793374. Its totient is φ = 6270264456.
The previous prime is 12540528911. The next prime is 12540528937. The reversal of 12540528914 is 41982504521.
12540528914 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41982504521 = 3727 ⋅11264423.
It can be written as a sum of positive squares in only one way, i.e., 12458354689 + 82174225 = 111617^2 + 9065^2 .
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (12540528911) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3135132227 + ... + 3135132230.
Almost surely, 212540528914 is an apocalyptic number.
12540528914 is a deficient number, since it is larger than the sum of its proper divisors (6270264460).
12540528914 is an equidigital number, since it uses as much as digits as its factorization.
12540528914 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6270264459.
The product of its (nonzero) digits is 115200, while the sum is 41.
The spelling of 12540528914 in words is "twelve billion, five hundred forty million, five hundred twenty-eight thousand, nine hundred fourteen".
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