12543412210055 has 4 divisors (see below), whose sum is σ = 15052094652072. Its totient is φ = 10034729768040.

The previous prime is 12543412210031. The next prime is 12543412210073. The reversal of 12543412210055 is 55001221434521.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-12543412210055 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12543412209997 and 12543412210024.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1254341221001 + ... + 1254341221010.

It is an arithmetic number, because the mean of its divisors is an integer number (3763023663018).

Almost surely, 2^{12543412210055} is an apocalyptic number.

12543412210055 is a deficient number, since it is larger than the sum of its proper divisors (2508682442017).

12543412210055 is an equidigital number, since it uses as much as digits as its factorization.

12543412210055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2508682442016.

The product of its (nonzero) digits is 48000, while the sum is 35.

Adding to 12543412210055 its reverse (55001221434521), we get a palindrome (67544633644576).

The spelling of 12543412210055 in words is "twelve trillion, five hundred forty-three billion, four hundred twelve million, two hundred ten thousand, fifty-five".