1254341706473 has 4 divisors (see below), whose sum is σ = 1254344469588. Its totient is φ = 1254338943360.

The previous prime is 1254341706463. The next prime is 1254341706481. The reversal of 1254341706473 is 3746071434521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1173209589904 + 81132116569 = 1083148^2 + 284837^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1254341706473 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1254341706433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 522608 + ... + 1667873.

It is an arithmetic number, because the mean of its divisors is an integer number (313586117397).

Almost surely, 2^{1254341706473} is an apocalyptic number.

It is an amenable number.

1254341706473 is a deficient number, since it is larger than the sum of its proper divisors (2763115).

1254341706473 is an equidigital number, since it uses as much as digits as its factorization.

1254341706473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2763114.

The product of its (nonzero) digits is 1693440, while the sum is 47.

The spelling of 1254341706473 in words is "one trillion, two hundred fifty-four billion, three hundred forty-one million, seven hundred six thousand, four hundred seventy-three".