Base | Representation |
---|---|
bin | 11100100001010100110110… |
… | …100100001001001011011011 |
3 | 121110010111210011021111201102 |
4 | 130201110312210021023123 |
5 | 112420113232420332443 |
6 | 1122440124331342015 |
7 | 35264261010140231 |
oct | 3441246644111333 |
9 | 543114704244642 |
10 | 125435435324123 |
11 | 36a70962166601 |
12 | 1209a2895b190b |
13 | 54cb6842b1982 |
14 | 22d9170c42951 |
15 | e77ce4640cb8 |
hex | 7215369092db |
125435435324123 has 4 divisors (see below), whose sum is σ = 125437456810368. Its totient is φ = 125433413837880.
The previous prime is 125435435324113. The next prime is 125435435324137. The reversal of 125435435324123 is 321423534534521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 125435435324123 - 222 = 125435431129819 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (125435435324113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1010650043 + ... + 1010774148.
It is an arithmetic number, because the mean of its divisors is an integer number (31359364202592).
Almost surely, 2125435435324123 is an apocalyptic number.
125435435324123 is a deficient number, since it is larger than the sum of its proper divisors (2021486245).
125435435324123 is an equidigital number, since it uses as much as digits as its factorization.
125435435324123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2021486244.
The product of its digits is 5184000, while the sum is 47.
Adding to 125435435324123 its reverse (321423534534521), we get a palindrome (446858969858644).
The spelling of 125435435324123 in words is "one hundred twenty-five trillion, four hundred thirty-five billion, four hundred thirty-five million, three hundred twenty-four thousand, one hundred twenty-three".
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