Base | Representation |
---|---|
bin | 11100100001011001100000… |
… | …010101101101111111101101 |
3 | 121110010222200022210220202111 |
4 | 130201121200111231333231 |
5 | 112420204000333400013 |
6 | 1122442312153324021 |
7 | 35264525552033335 |
oct | 3441314025557755 |
9 | 543128608726674 |
10 | 125440431153133 |
11 | 36a72a96184908 |
12 | 1209b242706611 |
13 | 54cbc9c30cc05 |
14 | 22d94c653a0c5 |
15 | e77ed802173d |
hex | 72166056dfed |
125440431153133 has 16 divisors (see below), whose sum is σ = 125738584980736. Its totient is φ = 125142610435200.
The previous prime is 125440431153061. The next prime is 125440431153229. The reversal of 125440431153133 is 331351134044521.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-125440431153133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (125440431153533) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10447269016 + ... + 10447281022.
It is an arithmetic number, because the mean of its divisors is an integer number (7858661561296).
Almost surely, 2125440431153133 is an apocalyptic number.
It is an amenable number.
125440431153133 is a deficient number, since it is larger than the sum of its proper divisors (298153827603).
125440431153133 is a wasteful number, since it uses less digits than its factorization.
125440431153133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23884.
The product of its (nonzero) digits is 259200, while the sum is 40.
Adding to 125440431153133 its reverse (331351134044521), we get a palindrome (456791565197654).
The spelling of 125440431153133 in words is "one hundred twenty-five trillion, four hundred forty billion, four hundred thirty-one million, one hundred fifty-three thousand, one hundred thirty-three".
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