Base | Representation |
---|---|
bin | 111010011010011011… |
… | …1100011100010111111 |
3 | 102222210012102120221111 |
4 | 1310310313203202333 |
5 | 4023400400432320 |
6 | 133343220342451 |
7 | 12030355110415 |
oct | 1646467434277 |
9 | 388705376844 |
10 | 125441030335 |
11 | 49221211805 |
12 | 20389b44a27 |
13 | baa152204a |
14 | 60ddc0d2b5 |
15 | 33e29c7a5a |
hex | 1d34de38bf |
125441030335 has 16 divisors (see below), whose sum is σ = 151133130720. Its totient is φ = 99950972800.
The previous prime is 125441030321. The next prime is 125441030399. The reversal of 125441030335 is 533030144521.
It is not a de Polignac number, because 125441030335 - 27 = 125441030207 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 125441030297 and 125441030306.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1317444 + ... + 1409446.
It is an arithmetic number, because the mean of its divisors is an integer number (9445820670).
Almost surely, 2125441030335 is an apocalyptic number.
125441030335 is a deficient number, since it is larger than the sum of its proper divisors (25692100385).
125441030335 is an equidigital number, since it uses as much as digits as its factorization.
125441030335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 93098.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 125441030335 its reverse (533030144521), we get a palindrome (658471174856).
The spelling of 125441030335 in words is "one hundred twenty-five billion, four hundred forty-one million, thirty thousand, three hundred thirty-five".
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