Base | Representation |
---|---|
bin | 1011011010001100010001… |
… | …1100100001000011111111 |
3 | 1122102020210202122112010120 |
4 | 2312203010130201003333 |
5 | 3121012320140022421 |
6 | 42402524304510023 |
7 | 2433213614214225 |
oct | 266430434410377 |
9 | 48366722575116 |
10 | 12544600314111 |
11 | 3aa7153927428 |
12 | 14a728931b313 |
13 | 6ccc489ba168 |
14 | 31523a34cb15 |
15 | 16b4a93418c6 |
hex | b68c47210ff |
12544600314111 has 8 divisors (see below), whose sum is σ = 16732000523904. Its totient is φ = 8360133490200.
The previous prime is 12544600314083. The next prime is 12544600314119. The reversal of 12544600314111 is 11141300644521.
12544600314111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12544600314111 - 27 = 12544600313983 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12544600314119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 733336491 + ... + 733353596.
It is an arithmetic number, because the mean of its divisors is an integer number (2091500065488).
Almost surely, 212544600314111 is an apocalyptic number.
12544600314111 is a deficient number, since it is larger than the sum of its proper divisors (4187400209793).
12544600314111 is a wasteful number, since it uses less digits than its factorization.
12544600314111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1466692941.
The product of its (nonzero) digits is 11520, while the sum is 33.
Adding to 12544600314111 its reverse (11141300644521), we get a palindrome (23685900958632).
The spelling of 12544600314111 in words is "twelve trillion, five hundred forty-four billion, six hundred million, three hundred fourteen thousand, one hundred eleven".
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