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12545113 = 71792159
BaseRepresentation
bin101111110110…
…110001011001
3212121100122211
4233312301121
511202420423
61124515121
7211426450
oct57666131
925540584
1012545113
117099369
12424baa1
1327a3159
141947b97
15117c10d
hexbf6c59

12545113 has 4 divisors (see below), whose sum is σ = 14337280. Its totient is φ = 10752948.

The previous prime is 12545089. The next prime is 12545129. The reversal of 12545113 is 31154521.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31154521 = 85736353.

It is a cyclic number.

It is not a de Polignac number, because 12545113 - 29 = 12544601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12545413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 896073 + ... + 896086.

It is an arithmetic number, because the mean of its divisors is an integer number (3584320).

Almost surely, 212545113 is an apocalyptic number.

It is an amenable number.

12545113 is a deficient number, since it is larger than the sum of its proper divisors (1792167).

12545113 is an equidigital number, since it uses as much as digits as its factorization.

12545113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1792166.

The product of its digits is 600, while the sum is 22.

The square root of 12545113 is about 3541.9081015746. The cubic root of 12545113 is about 232.3583011403.

Adding to 12545113 its reverse (31154521), we get a palindrome (43699634).

The spelling of 12545113 in words is "twelve million, five hundred forty-five thousand, one hundred thirteen".

Divisors: 1 7 1792159 12545113