Base | Representation |
---|---|
bin | 11100100001100110010101… |
… | …110101010110100111011011 |
3 | 121110012022020211210201200000 |
4 | 130201212111311112213123 |
5 | 112420420212131242230 |
6 | 1122452511533544043 |
7 | 35265524235300222 |
oct | 3441462565264733 |
9 | 543168224721600 |
10 | 125454213540315 |
11 | 36a78918a60340 |
12 | 120a1a4a345023 |
13 | 5500387808aba |
14 | 22da032b67cb9 |
15 | e78542ebbb60 |
hex | 721995d569db |
125454213540315 has 48 divisors (see below), whose sum is σ = 246008531897856. Its totient is φ = 60826285346400.
The previous prime is 125454213540301. The next prime is 125454213540329. The reversal of 125454213540315 is 513045312454521.
125454213540315 is a `hidden beast` number, since 1 + 2 + 5 + 4 + 54 + 21 + 3 + 540 + 31 + 5 = 666.
It is an interprime number because it is at equal distance from previous prime (125454213540301) and next prime (125454213540329).
It is not a de Polignac number, because 125454213540315 - 218 = 125454213278171 is a prime.
It is a super-2 number, since 2×1254542135403152 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4693372851 + ... + 4693399580.
It is an arithmetic number, because the mean of its divisors is an integer number (5125177747872).
Almost surely, 2125454213540315 is an apocalyptic number.
125454213540315 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
125454213540315 is a deficient number, since it is larger than the sum of its proper divisors (120554318357541).
125454213540315 is an equidigital number, since it uses as much as digits as its factorization.
125454213540315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9386772462 (or 9386772450 counting only the distinct ones).
The product of its (nonzero) digits is 1440000, while the sum is 45.
Adding to 125454213540315 its reverse (513045312454521), we get a palindrome (638499525994836).
The spelling of 125454213540315 in words is "one hundred twenty-five trillion, four hundred fifty-four billion, two hundred thirteen million, five hundred forty thousand, three hundred fifteen".
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