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125472300051 = 375974871431
BaseRepresentation
bin111010011011010111…
…0110101110000010011
3102222212101021020221010
41310312232311300103
54023431402100201
6133350254502003
712031214644650
oct1646656656023
9388771236833
10125472300051
114923792a14a
1220398504903
13baa7b4cc37
14610402cc27
1533e5602bd6
hex1d36bb5c13

125472300051 has 8 divisors (see below), whose sum is σ = 191195885824. Its totient is φ = 71698457160.

The previous prime is 125472300047. The next prime is 125472300059. The reversal of 125472300051 is 150003274521.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 125472300051 - 22 = 125472300047 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 125472299991 and 125472300018.

It is not an unprimeable number, because it can be changed into a prime (125472300059) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2987435695 + ... + 2987435736.

It is an arithmetic number, because the mean of its divisors is an integer number (23899485728).

Almost surely, 2125472300051 is an apocalyptic number.

125472300051 is a deficient number, since it is larger than the sum of its proper divisors (65723585773).

125472300051 is an equidigital number, since it uses as much as digits as its factorization.

125472300051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5974871441.

The product of its (nonzero) digits is 8400, while the sum is 30.

Adding to 125472300051 its reverse (150003274521), we get a palindrome (275475574572).

The spelling of 125472300051 in words is "one hundred twenty-five billion, four hundred seventy-two million, three hundred thousand, fifty-one".

Divisors: 1 3 7 21 5974871431 17924614293 41824100017 125472300051