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12550214113 = 17738247889
BaseRepresentation
bin10111011000000110…
…10001000111100001
31012101122102221012221
423230003101013201
5201200323322423
65433202351041
7623002026343
oct135403210741
935348387187
1012550214113
1153602a5688
12252305b481
13125014b5c8
14870b25293
154d6c06e5d
hex2ec0d11e1

12550214113 has 4 divisors (see below), whose sum is σ = 13288462020. Its totient is φ = 11811966208.

The previous prime is 12550214107. The next prime is 12550214123. The reversal of 12550214113 is 31141205521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7696026529 + 4854187584 = 87727^2 + 69672^2 .

It is a cyclic number.

It is not a de Polignac number, because 12550214113 - 25 = 12550214081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12550214123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 369123928 + ... + 369123961.

It is an arithmetic number, because the mean of its divisors is an integer number (3322115505).

Almost surely, 212550214113 is an apocalyptic number.

It is an amenable number.

12550214113 is a deficient number, since it is larger than the sum of its proper divisors (738247907).

12550214113 is an equidigital number, since it uses as much as digits as its factorization.

12550214113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 738247906.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 12550214113 its reverse (31141205521), we get a palindrome (43691419634).

The spelling of 12550214113 in words is "twelve billion, five hundred fifty million, two hundred fourteen thousand, one hundred thirteen".

Divisors: 1 17 738247889 12550214113