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12550503511151 = 112684311137757
BaseRepresentation
bin1011011010100010010001…
…0011011011010001101111
31122102211001011120000002222
42312220210103123101233
53121111412344324101
642405342142505555
72433513114444224
oct266504423332157
948384034500088
1012550503511151
113aa970304a771
1214a84562952bb
137006799c1668
1431563a35d94b
1516b70270701b
hexb6a244db46f

12550503511151 has 4 divisors (see below), whose sum is σ = 12550515775752. Its totient is φ = 12550491246552.

The previous prime is 12550503511127. The next prime is 12550503511223. The reversal of 12550503511151 is 15111530505521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12550503511151 - 222 = 12550499316847 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12550503561151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4442036 + ... + 6695721.

It is an arithmetic number, because the mean of its divisors is an integer number (3137628943938).

Almost surely, 212550503511151 is an apocalyptic number.

12550503511151 is a deficient number, since it is larger than the sum of its proper divisors (12264601).

12550503511151 is a wasteful number, since it uses less digits than its factorization.

12550503511151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12264600.

The product of its (nonzero) digits is 18750, while the sum is 35.

The spelling of 12550503511151 in words is "twelve trillion, five hundred fifty billion, five hundred three million, five hundred eleven thousand, one hundred fifty-one".

Divisors: 1 1126843 11137757 12550503511151