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1255123035253 = 8831421430391
BaseRepresentation
bin10010010000111011001…
…010011010010001110101
311102222200200102102210201
4102100323022122101311
5131030442444112003
62400332350320501
7156452055525433
oct22207312322165
94388620372721
101255123035253
1144432726137a
121833021b9131
1391485833929
1444a693c5d53
15229ae1dbb1d
hex1243b29a475

1255123035253 has 4 divisors (see below), whose sum is σ = 1256544466528. Its totient is φ = 1253701603980.

The previous prime is 1255123035251. The next prime is 1255123035359. The reversal of 1255123035253 is 3525303215521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1255123035253 - 21 = 1255123035251 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1255123035251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 710714313 + ... + 710716078.

It is an arithmetic number, because the mean of its divisors is an integer number (314136116632).

Almost surely, 21255123035253 is an apocalyptic number.

It is an amenable number.

1255123035253 is a deficient number, since it is larger than the sum of its proper divisors (1421431275).

1255123035253 is an equidigital number, since it uses as much as digits as its factorization.

1255123035253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1421431274.

The product of its (nonzero) digits is 135000, while the sum is 37.

The spelling of 1255123035253 in words is "one trillion, two hundred fifty-five billion, one hundred twenty-three million, thirty-five thousand, two hundred fifty-three".

Divisors: 1 883 1421430391 1255123035253