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125520793793 = 773511622743
BaseRepresentation
bin111010011100110011…
…1110101000011000001
3102222222202111222211122
41310321213311003001
54024031310400133
6133355150122025
712032344100063
oct1647147650301
9388882458748
10125520793793
114926224121a
12203b07b0315
13bab4bcb865
14610a653733
1533e99d1498
hex1d399f50c1

125520793793 has 4 divisors (see below), whose sum is σ = 125522493888. Its totient is φ = 125519093700.

The previous prime is 125520793777. The next prime is 125520793799. The reversal of 125520793793 is 397397025521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 397397025521 = 802794950199.

It is a cyclic number.

It is not a de Polignac number, because 125520793793 - 24 = 125520793777 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (125520793799) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 734021 + ... + 888722.

It is an arithmetic number, because the mean of its divisors is an integer number (31380623472).

Almost surely, 2125520793793 is an apocalyptic number.

It is an amenable number.

125520793793 is a deficient number, since it is larger than the sum of its proper divisors (1700095).

125520793793 is an equidigital number, since it uses as much as digits as its factorization.

125520793793 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1700094.

The product of its (nonzero) digits is 3572100, while the sum is 53.

The spelling of 125520793793 in words is "one hundred twenty-five billion, five hundred twenty million, seven hundred ninety-three thousand, seven hundred ninety-three".

Divisors: 1 77351 1622743 125520793793