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125535033000 = 2332531319149379
BaseRepresentation
bin111010011101001111…
…0001001011010101000
3110000000202022102100200
41310322132021122220
54024043432024000
6133400415232200
712032606113566
oct1647236113250
9400022272320
10125535033000
114926a287363
12203b5518660
13bab7b45b20
14610c4bca36
1533ead95500
hex1d3a7896a8

125535033000 has 768 divisors, whose sum is σ = 485503200000. Its totient is φ = 29001369600.

The previous prime is 125535032969. The next prime is 125535033031. The reversal of 125535033000 is 330535521.

125535033000 is a `hidden beast` number, since 1 + 2 + 5 + 5 + 350 + 3 + 300 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (125535032969) and next prime (125535033031).

It is a super-2 number, since 2×1255350330002 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 331226811 + ... + 331227189.

It is an arithmetic number, because the mean of its divisors is an integer number (632165625).

Almost surely, 2125535033000 is an apocalyptic number.

125535033000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 125535033000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (242751600000).

125535033000 is an abundant number, since it is smaller than the sum of its proper divisors (359968167000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

125535033000 is a wasteful number, since it uses less digits than its factorization.

125535033000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 587 (or 570 counting only the distinct ones).

The product of its (nonzero) digits is 6750, while the sum is 27.

Adding to 125535033000 its reverse (330535521), we get a palindrome (125865568521).

The spelling of 125535033000 in words is "one hundred twenty-five billion, five hundred thirty-five million, thirty-three thousand".