12553903 has 4 divisors (see below), whose sum is σ = 12561120. Its totient is φ = 12546688.

The previous prime is 12553901. The next prime is 12553909. The reversal of 12553903 is 30935521.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 30935521 = 151 ⋅204871.

It is a cyclic number.

It is not a de Polignac number, because 12553903 - 2¹ = 12553901 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12553901) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 783 + ... + 5071.

It is an arithmetic number, because the mean of its divisors is an integer number (3140280).

Almost surely, 2^12553903 is an apocalyptic number.

12553903 is a deficient number, since it is larger than the sum of its proper divisors (7217).

12553903 is an equidigital number, since it uses as much as digits as its factorization.

12553903 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7216.

The product of its (nonzero) digits is 4050, while the sum is 28.

The square root of 12553903 is about 3543.1487408801. The cubic root of 12553903 is about 232.4125573974.

It can be divided in two parts, 12553 and 903, that added together give a square (13456 = 116²).

The spelling of 12553903 in words is "twelve million, five hundred fifty-three thousand, nine hundred three".