Base | Representation |
---|---|
bin | 1011011011000101101010… |
… | …1100101010011100110001 |
3 | 1122110201120102020000222020 |
4 | 2312301122230222130301 |
5 | 3121240343020444103 |
6 | 42413553114502053 |
7 | 2434300441516200 |
oct | 266613254523461 |
9 | 48421512200866 |
10 | 12560006031153 |
11 | 4002739a69689 |
12 | 14aa268734929 |
13 | 7015325c9a69 |
14 | 315c9c3c5237 |
15 | 16baaba98753 |
hex | b6c5ab2a731 |
12560006031153 has 24 divisors (see below), whose sum is σ = 19481236012800. Its totient is φ = 7176995128800.
The previous prime is 12560006031149. The next prime is 12560006031173. The reversal of 12560006031153 is 35113060006521.
It is not a de Polignac number, because 12560006031153 - 22 = 12560006031149 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12560006031173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6298003 + ... + 8048903.
It is an arithmetic number, because the mean of its divisors is an integer number (811718167200).
Almost surely, 212560006031153 is an apocalyptic number.
It is an amenable number.
12560006031153 is a deficient number, since it is larger than the sum of its proper divisors (6921229981647).
12560006031153 is a wasteful number, since it uses less digits than its factorization.
12560006031153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1799717 (or 1799710 counting only the distinct ones).
The product of its (nonzero) digits is 16200, while the sum is 33.
Adding to 12560006031153 its reverse (35113060006521), we get a palindrome (47673066037674).
The spelling of 12560006031153 in words is "twelve trillion, five hundred sixty billion, six million, thirty-one thousand, one hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •