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12561145601234 = 26280572800617
BaseRepresentation
bin1011011011001001111010…
…0111110001110011010010
31122110211111211112012020112
42312302132213301303102
53121300211233214414
642414302143441322
72434340616640016
oct266623647616322
948424454465215
1012561145601234
11400317425053a
1214aa5262b6242
13701684723699
14315d698a4546
1516bb26b48d3e
hexb6c9e9f1cd2

12561145601234 has 4 divisors (see below), whose sum is σ = 18841718401854. Its totient is φ = 6280572800616.

The previous prime is 12561145601227. The next prime is 12561145601299. The reversal of 12561145601234 is 43210654116521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9582770316025 + 2978375285209 = 3095605^2 + 1725797^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12561145601191 and 12561145601200.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3140286400307 + ... + 3140286400310.

Almost surely, 212561145601234 is an apocalyptic number.

12561145601234 is a deficient number, since it is larger than the sum of its proper divisors (6280572800620).

12561145601234 is an equidigital number, since it uses as much as digits as its factorization.

12561145601234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6280572800619.

The product of its (nonzero) digits is 172800, while the sum is 41.

Adding to 12561145601234 its reverse (43210654116521), we get a palindrome (55771799717755).

The spelling of 12561145601234 in words is "twelve trillion, five hundred sixty-one billion, one hundred forty-five million, six hundred one thousand, two hundred thirty-four".

Divisors: 1 2 6280572800617 12561145601234