Base | Representation |
---|---|
bin | 10111011100110010… |
… | …11001000101000011 |
3 | 1012111101111100001021 |
4 | 23232121121011003 |
5 | 201240412141243 |
6 | 5441130050311 |
7 | 623660364553 |
oct | 135631310503 |
9 | 35441440037 |
10 | 12589568323 |
11 | 5380535022 |
12 | 2534279997 |
13 | 125834a217 |
14 | 87604b163 |
15 | 4da3cc6ed |
hex | 2ee659143 |
12589568323 has 4 divisors (see below), whose sum is σ = 12621280480. Its totient is φ = 12557856168.
The previous prime is 12589568269. The next prime is 12589568333. The reversal of 12589568323 is 32386598521.
12589568323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12589568323 - 213 = 12589560131 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12589568333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15855483 + ... + 15856276.
It is an arithmetic number, because the mean of its divisors is an integer number (3155320120).
Almost surely, 212589568323 is an apocalyptic number.
12589568323 is a deficient number, since it is larger than the sum of its proper divisors (31712157).
12589568323 is an equidigital number, since it uses as much as digits as its factorization.
12589568323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31712156.
The product of its digits is 3110400, while the sum is 52.
The spelling of 12589568323 in words is "twelve billion, five hundred eighty-nine million, five hundred sixty-eight thousand, three hundred twenty-three".
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