Base | Representation |
---|---|
bin | 100111100101101110010… |
… | …0111111011001100000111 |
3 | 201021011111201010112111201 |
4 | 1033023130213323030013 |
5 | 1203121413243102221 |
6 | 15323342020243331 |
7 | 1101052163215234 |
oct | 117133447731407 |
9 | 21234451115451 |
10 | 5441130050311 |
11 | 180863007747a |
12 | 73a63b540547 |
13 | 306133927687 |
14 | 14b4d023878b |
15 | 96809e21891 |
hex | 4f2dc9fb307 |
5441130050311 has 4 divisors (see below), whose sum is σ = 5442115946400. Its totient is φ = 5440144154224.
The previous prime is 5441130050309. The next prime is 5441130050327. The reversal of 5441130050311 is 1130500311445.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5441130050311 - 21 = 5441130050309 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5441130050311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5441130050711) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 492939766 + ... + 492950803.
It is an arithmetic number, because the mean of its divisors is an integer number (1360528986600).
Almost surely, 25441130050311 is an apocalyptic number.
5441130050311 is a deficient number, since it is larger than the sum of its proper divisors (985896089).
5441130050311 is an equidigital number, since it uses as much as digits as its factorization.
5441130050311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 985896088.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 5441130050311 its reverse (1130500311445), we get a palindrome (6571630361756).
The spelling of 5441130050311 in words is "five trillion, four hundred forty-one billion, one hundred thirty million, fifty thousand, three hundred eleven".
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