Base | Representation |
---|---|
bin | 10111011111100101… |
… | …10010101011111101 |
3 | 1012120000120222210101 |
4 | 23233302302223331 |
5 | 201312412112104 |
6 | 5443324241101 |
7 | 624363523333 |
oct | 135762625375 |
9 | 35500528711 |
10 | 12613004029 |
11 | 539279167a |
12 | 25400a0191 |
13 | 12601643c2 |
14 | 8791cbb53 |
15 | 4dc4ab5a4 |
hex | 2efcb2afd |
12613004029 has 4 divisors (see below), whose sum is σ = 12631471776. Its totient is φ = 12594536284.
The previous prime is 12613004009. The next prime is 12613004039. The reversal of 12613004029 is 92040031621.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12613004029 - 29 = 12613003517 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12613003988 and 12613004006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12613004009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9232849 + ... + 9234214.
It is an arithmetic number, because the mean of its divisors is an integer number (3157867944).
Almost surely, 212613004029 is an apocalyptic number.
It is an amenable number.
12613004029 is a deficient number, since it is larger than the sum of its proper divisors (18467747).
12613004029 is an equidigital number, since it uses as much as digits as its factorization.
12613004029 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18467746.
The product of its (nonzero) digits is 2592, while the sum is 28.
The spelling of 12613004029 in words is "twelve billion, six hundred thirteen million, four thousand, twenty-nine".
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