Base | Representation |
---|---|
bin | 1011011110110000011010… |
… | …1001111111101110000111 |
3 | 1122200202020000011112020010 |
4 | 2313230012221333232013 |
5 | 3123303421230231033 |
6 | 42502534030441303 |
7 | 2441661134240445 |
oct | 267540651775607 |
9 | 48622200145203 |
10 | 12623020555143 |
11 | 4027436027189 |
12 | 14ba514063233 |
13 | 70746575524b |
14 | 318d59381b95 |
15 | 16d548cad863 |
hex | b7b06a7fb87 |
12623020555143 has 8 divisors (see below), whose sum is σ = 17411062834800. Its totient is φ = 8125162656128.
The previous prime is 12623020555129. The next prime is 12623020555177. The reversal of 12623020555143 is 34155502032621.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12623020555143 - 28 = 12623020554887 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12623020555193) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 72546095058 + ... + 72546095231.
It is an arithmetic number, because the mean of its divisors is an integer number (2176382854350).
Almost surely, 212623020555143 is an apocalyptic number.
12623020555143 is a deficient number, since it is larger than the sum of its proper divisors (4788042279657).
12623020555143 is a wasteful number, since it uses less digits than its factorization.
12623020555143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 145092190321.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 12623020555143 its reverse (34155502032621), we get a palindrome (46778522587764).
The spelling of 12623020555143 in words is "twelve trillion, six hundred twenty-three billion, twenty million, five hundred fifty-five thousand, one hundred forty-three".
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