1263983935207 has 16 divisors (see below), whose sum is σ = 1455181516800. Its totient is φ = 1075444383168.

The previous prime is 1263983935189. The next prime is 1263983935237. The reversal of 1263983935207 is 7025393893621.

It is a cyclic number.

It is not a de Polignac number, because 1263983935207 - 2¹⁵ = 1263983902439 is a prime.

It is a super-2 number, since 2×1263983935207² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1263983935237) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25291678 + ... + 25341604.

It is an arithmetic number, because the mean of its divisors is an integer number (90948844800).

Almost surely, 2^{1263983935207} is an apocalyptic number.

1263983935207 is a deficient number, since it is larger than the sum of its proper divisors (191197581593).

1263983935207 is a wasteful number, since it uses less digits than its factorization.

1263983935207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76470.

The product of its (nonzero) digits is 14696640, while the sum is 58.

The spelling of 1263983935207 in words is "one trillion, two hundred sixty-three billion, nine hundred eighty-three million, nine hundred thirty-five thousand, two hundred seven".