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12641316443439 = 37953338887947
BaseRepresentation
bin1011011111110100100100…
…1011010001010100101111
31122202111110002002221200120
42313331021023101110233
53124103404002142224
642515201323100023
72443206414565605
oct267751113212457
948674402087616
1012641316443439
114034174634922
121501b7b371613
137090c0073c58
14319bb31d1875
1516dc6a112779
hexb7f492d152f

12641316443439 has 8 divisors (see below), whose sum is σ = 17068444143360. Its totient is φ = 8320866519576.

The previous prime is 12641316443381. The next prime is 12641316443461. The reversal of 12641316443439 is 93434461314621.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12641316443439 - 29 = 12641316442927 is a prime.

It is a super-2 number, since 2×126413164434392 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12641316443391 and 12641316443400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12641316443339) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26669443737 + ... + 26669444210.

It is an arithmetic number, because the mean of its divisors is an integer number (2133555517920).

Almost surely, 212641316443439 is an apocalyptic number.

12641316443439 is a deficient number, since it is larger than the sum of its proper divisors (4427127699921).

12641316443439 is an equidigital number, since it uses as much as digits as its factorization.

12641316443439 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53338888029.

The product of its digits is 4478976, while the sum is 51.

The spelling of 12641316443439 in words is "twelve trillion, six hundred forty-one billion, three hundred sixteen million, four hundred forty-three thousand, four hundred thirty-nine".

Divisors: 1 3 79 237 53338887947 160016663841 4213772147813 12641316443439