Base | Representation |
---|---|
bin | 10111100011010000… |
… | …11101110011001111 |
3 | 1012122011122012112020 |
4 | 23301220131303033 |
5 | 201343311221341 |
6 | 5450345341223 |
7 | 625216651506 |
oct | 136150356317 |
9 | 35564565466 |
10 | 12643851471 |
11 | 53a9140829 |
12 | 254a497813 |
13 | 1266675024 |
14 | 87d33b83d |
15 | 4e0051566 |
hex | 2f1a1dccf |
12643851471 has 4 divisors (see below), whose sum is σ = 16858468632. Its totient is φ = 8429234312.
The previous prime is 12643851431. The next prime is 12643851523. The reversal of 12643851471 is 17415834621.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12643851471 - 211 = 12643849423 is a prime.
It is a super-3 number, since 3×126438514713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12643851401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2107308576 + ... + 2107308581.
It is an arithmetic number, because the mean of its divisors is an integer number (4214617158).
Almost surely, 212643851471 is an apocalyptic number.
12643851471 is a deficient number, since it is larger than the sum of its proper divisors (4214617161).
12643851471 is an equidigital number, since it uses as much as digits as its factorization.
12643851471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4214617160.
The product of its digits is 161280, while the sum is 42.
The spelling of 12643851471 in words is "twelve billion, six hundred forty-three million, eight hundred fifty-one thousand, four hundred seventy-one".
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