Base | Representation |
---|---|
bin | 1011100000011010010000… |
… | …0111111001100111010010 |
3 | 1122210110120001201200221212 |
4 | 2320012210013321213102 |
5 | 3124240113122034023 |
6 | 42523553203220122 |
7 | 2444015166355064 |
oct | 270064407714722 |
9 | 48713501650855 |
10 | 12651432221138 |
11 | 4038495737387 |
12 | 1503b23077642 |
13 | 70a042a3a529 |
14 | 31a492891734 |
15 | 16e15d23ee78 |
hex | b81a41f99d2 |
12651432221138 has 4 divisors (see below), whose sum is σ = 18977148331710. Its totient is φ = 6325716110568.
The previous prime is 12651432221107. The next prime is 12651432221159. The reversal of 12651432221138 is 83112223415621.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8441889573049 + 4209542648089 = 2905493^2 + 2051717^2 .
It is a junction number, because it is equal to n+sod(n) for n = 12651432221095 and 12651432221104.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3162858055283 + ... + 3162858055286.
Almost surely, 212651432221138 is an apocalyptic number.
12651432221138 is a deficient number, since it is larger than the sum of its proper divisors (6325716110572).
12651432221138 is an equidigital number, since it uses as much as digits as its factorization.
12651432221138 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6325716110571.
The product of its digits is 138240, while the sum is 41.
Adding to 12651432221138 its reverse (83112223415621), we get a palindrome (95763655636759).
The spelling of 12651432221138 in words is "twelve trillion, six hundred fifty-one billion, four hundred thirty-two million, two hundred twenty-one thousand, one hundred thirty-eight".
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