Base | Representation |
---|---|
bin | 111010111011111010… |
… | …1001110101110101101 |
3 | 110002200111102110201020 |
4 | 1311313311032232231 |
5 | 4033201002304003 |
6 | 134050512204353 |
7 | 12100246310421 |
oct | 1656765165655 |
9 | 402614373636 |
10 | 126564494253 |
11 | 497483a288a |
12 | 206422396b9 |
13 | bc201c99b2 |
14 | 61a90d8b81 |
15 | 345b445d53 |
hex | 1d77d4ebad |
126564494253 has 4 divisors (see below), whose sum is σ = 168752659008. Its totient is φ = 84376329500.
The previous prime is 126564494237. The next prime is 126564494261. The reversal of 126564494253 is 352494465621.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 126564494253 - 24 = 126564494237 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 126564494196 and 126564494205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (126564494053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21094082373 + ... + 21094082378.
It is an arithmetic number, because the mean of its divisors is an integer number (42188164752).
Almost surely, 2126564494253 is an apocalyptic number.
It is an amenable number.
126564494253 is a deficient number, since it is larger than the sum of its proper divisors (42188164755).
126564494253 is an equidigital number, since it uses as much as digits as its factorization.
126564494253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42188164754.
The product of its digits is 6220800, while the sum is 51.
The spelling of 126564494253 in words is "one hundred twenty-six billion, five hundred sixty-four million, four hundred ninety-four thousand, two hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •