Base | Representation |
---|---|
bin | 10010011011000100011… |
… | …000001100010010001011 |
3 | 11111000210202200200101120 |
4 | 102123010120030102023 |
5 | 131220244323424011 |
6 | 2405333240250323 |
7 | 160316014315062 |
oct | 22330430142213 |
9 | 4430722620346 |
10 | 1266015061131 |
11 | 448a06551657 |
12 | 185441a709a3 |
13 | 92500285062 |
14 | 453bdbcb1d9 |
15 | 22dea54da06 |
hex | 126c460c48b |
1266015061131 has 4 divisors (see below), whose sum is σ = 1688020081512. Its totient is φ = 844010040752.
The previous prime is 1266015061063. The next prime is 1266015061189. The reversal of 1266015061131 is 1311605106621.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1266015061131 - 29 = 1266015060619 is a prime.
It is a super-2 number, since 2×12660150611312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1266015061092 and 1266015061101.
It is not an unprimeable number, because it can be changed into a prime (1266015066131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211002510186 + ... + 211002510191.
It is an arithmetic number, because the mean of its divisors is an integer number (422005020378).
Almost surely, 21266015061131 is an apocalyptic number.
1266015061131 is a deficient number, since it is larger than the sum of its proper divisors (422005020381).
1266015061131 is an equidigital number, since it uses as much as digits as its factorization.
1266015061131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 422005020380.
The product of its (nonzero) digits is 6480, while the sum is 33.
The spelling of 1266015061131 in words is "one trillion, two hundred sixty-six billion, fifteen million, sixty-one thousand, one hundred thirty-one".
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