Base | Representation |
---|---|
bin | 10111100101101111… |
… | …10001111011110101 |
3 | 1012200121202112120121 |
4 | 23302313301323311 |
5 | 201414122041232 |
6 | 5452411131541 |
7 | 625561456234 |
oct | 136267617365 |
9 | 35617675517 |
10 | 12664643317 |
11 | 5409951a77 |
12 | 2555443bb1 |
13 | 126aa749b1 |
14 | 881dd0b1b |
15 | 4e1cabd97 |
hex | 2f2df1ef5 |
12664643317 has 4 divisors (see below), whose sum is σ = 12673445760. Its totient is φ = 12655840876.
The previous prime is 12664643297. The next prime is 12664643333. The reversal of 12664643317 is 71334646621.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12664643317 - 215 = 12664610549 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12664643417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4399063 + ... + 4401940.
It is an arithmetic number, because the mean of its divisors is an integer number (3168361440).
Almost surely, 212664643317 is an apocalyptic number.
It is an amenable number.
12664643317 is a deficient number, since it is larger than the sum of its proper divisors (8802443).
12664643317 is an equidigital number, since it uses as much as digits as its factorization.
12664643317 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8802442.
The product of its digits is 435456, while the sum is 43.
The spelling of 12664643317 in words is "twelve billion, six hundred sixty-four million, six hundred forty-three thousand, three hundred seventeen".
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