Base | Representation |
---|---|
bin | 10010011011101110111… |
… | …001000010100100001011 |
3 | 11111002122110210201221222 |
4 | 102123232321002210023 |
5 | 131223224422041042 |
6 | 2405532115552255 |
7 | 160342465010621 |
oct | 22335671024413 |
9 | 4432573721858 |
10 | 1266728315147 |
11 | 449242123989 |
12 | 1856008bb68b |
13 | 925b4c85159 |
14 | 4544a815511 |
15 | 22e3ce8d2d2 |
hex | 126eee4290b |
1266728315147 has 4 divisors (see below), whose sum is σ = 1268514956640. Its totient is φ = 1264941673656.
The previous prime is 1266728315131. The next prime is 1266728315159. The reversal of 1266728315147 is 7415138276621.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1266728315147 - 24 = 1266728315131 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1266128315147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 893319683 + ... + 893321100.
It is an arithmetic number, because the mean of its divisors is an integer number (317128739160).
Almost surely, 21266728315147 is an apocalyptic number.
1266728315147 is a deficient number, since it is larger than the sum of its proper divisors (1786641493).
1266728315147 is an equidigital number, since it uses as much as digits as its factorization.
1266728315147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1786641492.
The product of its digits is 3386880, while the sum is 53.
The spelling of 1266728315147 in words is "one trillion, two hundred sixty-six billion, seven hundred twenty-eight million, three hundred fifteen thousand, one hundred forty-seven".
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