Base | Representation |
---|---|
bin | 1011100010100111011110… |
… | …1110101010111111011111 |
3 | 1122221002102001212212221210 |
4 | 2320221313232222333133 |
5 | 3130400233040201212 |
6 | 42553223035555503 |
7 | 2446526504222250 |
oct | 270516756527737 |
9 | 48832361785853 |
10 | 12689342115807 |
11 | 40525798a5345 |
12 | 150b342bbbb93 |
13 | 7107a4a87876 |
14 | 31c24b62ab27 |
15 | 17012b4b653c |
hex | b8a77baafdf |
12689342115807 has 16 divisors (see below), whose sum is σ = 19356688899072. Its totient is φ = 7243346938080.
The previous prime is 12689342115773. The next prime is 12689342115889. The reversal of 12689342115807 is 70851124398621.
It is not a de Polignac number, because 12689342115807 - 26 = 12689342115743 is a prime.
It is a super-2 number, since 2×126893421158072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12689342115407) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 321050583 + ... + 321090104.
It is an arithmetic number, because the mean of its divisors is an integer number (1209793056192).
It is a 1-persistent number, because it is pandigital, but 2⋅12689342115807 = 25378684231614 is not.
Almost surely, 212689342115807 is an apocalyptic number.
12689342115807 is a deficient number, since it is larger than the sum of its proper divisors (6667346783265).
12689342115807 is an equidigital number, since it uses as much as digits as its factorization.
12689342115807 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 642141638.
The product of its (nonzero) digits is 5806080, while the sum is 57.
The spelling of 12689342115807 in words is "twelve trillion, six hundred eighty-nine billion, three hundred forty-two million, one hundred fifteen thousand, eight hundred seven".
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