Base | Representation |
---|---|
bin | 1011100010111010111000… |
… | …1110010100110001110111 |
3 | 1122221120212002222102102000 |
4 | 2320232232032110301313 |
5 | 3130441420121203031 |
6 | 42555444003550343 |
7 | 2450102550045141 |
oct | 270565616246167 |
9 | 48846762872360 |
10 | 12694551350391 |
11 | 4054802322399 |
12 | 151035768b3b3 |
13 | 711125084ab1 |
14 | 31c5c33d5c91 |
15 | 17033399d3e6 |
hex | b8bae394c77 |
12694551350391 has 16 divisors (see below), whose sum is σ = 19315033087200. Its totient is φ = 8234303577984.
The previous prime is 12694551350357. The next prime is 12694551350401. The reversal of 12694551350391 is 19305315549621.
12694551350391 is a `hidden beast` number, since 1 + 2 + 6 + 9 + 4 + 551 + 3 + 50 + 39 + 1 = 666.
It is not a de Polignac number, because 12694551350391 - 27 = 12694551350263 is a prime.
It is a super-2 number, since 2×126945513503912 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12694551350311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6353628306 + ... + 6353630303.
It is an arithmetic number, because the mean of its divisors is an integer number (1207189567950).
Almost surely, 212694551350391 is an apocalyptic number.
12694551350391 is a deficient number, since it is larger than the sum of its proper divisors (6620481736809).
12694551350391 is a wasteful number, since it uses less digits than its factorization.
12694551350391 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12707258655 (or 12707258649 counting only the distinct ones).
The product of its (nonzero) digits is 4374000, while the sum is 54.
The spelling of 12694551350391 in words is "twelve trillion, six hundred ninety-four billion, five hundred fifty-one million, three hundred fifty thousand, three hundred ninety-one".
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