1269631312055 has 4 divisors (see below), whose sum is σ = 1523557574472. Its totient is φ = 1015705049640.

The previous prime is 1269631312021. The next prime is 1269631312063. The reversal of 1269631312055 is 5502131369621.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1269631312055 - 2³² = 1265336344759 is a prime.

It is a super-2 number, since 2×1269631312055² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1269631311997 and 1269631312015.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126963131201 + ... + 126963131210.

It is an arithmetic number, because the mean of its divisors is an integer number (380889393618).

Almost surely, 2^{1269631312055} is an apocalyptic number.

1269631312055 is a deficient number, since it is larger than the sum of its proper divisors (253926262417).

1269631312055 is an equidigital number, since it uses as much as digits as its factorization.

1269631312055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 253926262416.

The product of its (nonzero) digits is 291600, while the sum is 44.

The spelling of 1269631312055 in words is "one trillion, two hundred sixty-nine billion, six hundred thirty-one million, three hundred twelve thousand, fifty-five".