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12700396051 = 712011510693
BaseRepresentation
bin10111101010000000…
…01010101000010011
31012210010000222002221
423311000022220103
5202002300133201
65500125321511
7626504404510
oct136500125023
935703028087
1012700396051
115428051592
122565406297
1312752b2265
14886a5a307
154e4ec04a1
hex2f500aa13

12700396051 has 8 divisors (see below), whose sum is σ = 14526833504. Its totient is φ = 10876982400.

The previous prime is 12700396003. The next prime is 12700396069. The reversal of 12700396051 is 15069300721.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12700396051 - 213 = 12700387859 is a prime.

It is a super-2 number, since 2×127003960512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12700395998 and 12700396016.

It is not an unprimeable number, because it can be changed into a prime (12700396001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 746940 + ... + 763753.

It is an arithmetic number, because the mean of its divisors is an integer number (1815854188).

Almost surely, 212700396051 is an apocalyptic number.

12700396051 is a deficient number, since it is larger than the sum of its proper divisors (1826437453).

12700396051 is a wasteful number, since it uses less digits than its factorization.

12700396051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1511901.

The product of its (nonzero) digits is 11340, while the sum is 34.

Adding to 12700396051 its reverse (15069300721), we get a palindrome (27769696772).

The spelling of 12700396051 in words is "twelve billion, seven hundred million, three hundred ninety-six thousand, fifty-one".

Divisors: 1 7 1201 8407 1510693 10574851 1814342293 12700396051