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12707981439 = 34235993813
BaseRepresentation
bin10111101010111010…
…00110100001111111
31012210122022100022020
423311131012201333
5202011220401224
65501000051223
7626626026366
oct136535064177
935718270266
1012707981439
1154313625aa
122567a63b13
131276a39a5a
14887a727dd
154e59bcc79
hex2f574687f

12707981439 has 4 divisors (see below), whose sum is σ = 16943975256. Its totient is φ = 8471987624.

The previous prime is 12707981431. The next prime is 12707981441. The reversal of 12707981439 is 93418970721.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12707981439 - 23 = 12707981431 is a prime.

It is a super-2 number, since 2×127079814392 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12707981391 and 12707981400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12707981431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2117996904 + ... + 2117996909.

It is an arithmetic number, because the mean of its divisors is an integer number (4235993814).

Almost surely, 212707981439 is an apocalyptic number.

12707981439 is a deficient number, since it is larger than the sum of its proper divisors (4235993817).

12707981439 is an equidigital number, since it uses as much as digits as its factorization.

12707981439 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4235993816.

The product of its (nonzero) digits is 762048, while the sum is 51.

The spelling of 12707981439 in words is "twelve billion, seven hundred seven million, nine hundred eighty-one thousand, four hundred thirty-nine".

Divisors: 1 3 4235993813 12707981439