12713402041 has 4 divisors (see below), whose sum is σ = 12723130512. Its totient is φ = 12703673572.

The previous prime is 12713402027. The next prime is 12713402123. The reversal of 12713402041 is 14020431721.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12713402041 - 2⁷ = 12713401913 is a prime.

It is a super-2 number, since 2×12713402041² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12713401997 and 12713402015.

It is not an unprimeable number, because it can be changed into a prime (12713402021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4862275 + ... + 4864888.

It is an arithmetic number, because the mean of its divisors is an integer number (3180782628).

Almost surely, 2^12713402041 is an apocalyptic number.

It is an amenable number.

12713402041 is a deficient number, since it is larger than the sum of its proper divisors (9728471).

12713402041 is an equidigital number, since it uses as much as digits as its factorization.

12713402041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9728470.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 12713402041 its reverse (14020431721), we get a palindrome (26733833762).

The spelling of 12713402041 in words is "twelve billion, seven hundred thirteen million, four hundred two thousand, forty-one".