Base | Representation |
---|---|
bin | 10111101011100011… |
… | …11100111100000101 |
3 | 1012211000121000212211 |
4 | 23311301330330011 |
5 | 202014120302143 |
6 | 5501313143421 |
7 | 630023342440 |
oct | 136561747405 |
9 | 35730530784 |
10 | 12713447173 |
11 | 5434456039 |
12 | 256985ab71 |
13 | 1277c0180b |
14 | 888696657 |
15 | 4e61ec49d |
hex | 2f5c7cf05 |
12713447173 has 4 divisors (see below), whose sum is σ = 14529653920. Its totient is φ = 10897240428.
The previous prime is 12713447171. The next prime is 12713447191. The reversal of 12713447173 is 37174431721.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 37174431721 = 7 ⋅5310633103.
It is a cyclic number.
It is not a de Polignac number, because 12713447173 - 21 = 12713447171 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12713447171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 908103363 + ... + 908103376.
It is an arithmetic number, because the mean of its divisors is an integer number (3632413480).
Almost surely, 212713447173 is an apocalyptic number.
It is an amenable number.
12713447173 is a deficient number, since it is larger than the sum of its proper divisors (1816206747).
12713447173 is an equidigital number, since it uses as much as digits as its factorization.
12713447173 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1816206746.
The product of its digits is 98784, while the sum is 40.
Adding to 12713447173 its reverse (37174431721), we get a palindrome (49887878894).
The spelling of 12713447173 in words is "twelve billion, seven hundred thirteen million, four hundred forty-seven thousand, one hundred seventy-three".
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