127373432580113 has 4 divisors (see below), whose sum is σ = 128686560751140. Its totient is φ = 126060304409088.

The previous prime is 127373432580077. The next prime is 127373432580137. The reversal of 127373432580113 is 311085234373721.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 92252720909584 + 35120711670529 = 9604828^2 + 5926273^2 .

It is not a de Polignac number, because 127373432580113 - 2⁶ = 127373432580049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (127373432580193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 656564085368 + ... + 656564085561.

It is an arithmetic number, because the mean of its divisors is an integer number (32171640187785).

Almost surely, 2^{127373432580113} is an apocalyptic number.

It is an amenable number.

127373432580113 is a deficient number, since it is larger than the sum of its proper divisors (1313128171027).

127373432580113 is an equidigital number, since it uses as much as digits as its factorization.

127373432580113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1313128171026.

The product of its (nonzero) digits is 2540160, while the sum is 50.

The spelling of 127373432580113 in words is "one hundred twenty-seven trillion, three hundred seventy-three billion, four hundred thirty-two million, five hundred eighty thousand, one hundred thirteen".