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12803140000 = 25547109839
BaseRepresentation
bin10111110110010000…
…00110100110100000
31020001021100220022101
423323020012212200
5202210100440000
65514235420144
7632162615530
oct137310064640
936037326271
1012803140000
115480047642
1225938b4654
1312906769b1
148965634c0
154ee017e6a
hex2fb2069a0

12803140000 has 240 divisors, whose sum is σ = 36370857600. Its totient is φ = 4344192000.

The previous prime is 12803139997. The next prime is 12803140033. The reversal of 12803140000 is 4130821.

It is a self number, because there is not a number n which added to its sum of digits gives 12803140000.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 15259581 + ... + 15260419.

It is an arithmetic number, because the mean of its divisors is an integer number (151545240).

Almost surely, 212803140000 is an apocalyptic number.

12803140000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12803140000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18185428800).

12803140000 is an abundant number, since it is smaller than the sum of its proper divisors (23567717600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12803140000 is an equidigital number, since it uses as much as digits as its factorization.

12803140000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 985 (or 962 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 12803140000 its reverse (4130821), we get a palindrome (12807270821).

The spelling of 12803140000 in words is "twelve billion, eight hundred three million, one hundred forty thousand".