Base | Representation |
---|---|
bin | 11101000111000111001010… |
… | …011000111000110101101111 |
3 | 121210022202011111011012110022 |
4 | 131013013022120320311233 |
5 | 113240134142331221432 |
6 | 1132145042405232355 |
7 | 35653004121544262 |
oct | 3507071230706557 |
9 | 553282144135408 |
10 | 128032075648367 |
11 | 37882109a06850 |
12 | 124395831026bb |
13 | 56594b0428a07 |
14 | 2388add6a4cd9 |
15 | ec061c54bb12 |
hex | 7471ca638d6f |
128032075648367 has 16 divisors (see below), whose sum is σ = 148090738828032. Its totient is φ = 109395478389120.
The previous prime is 128032075648357. The next prime is 128032075648387. The reversal of 128032075648367 is 763846570230821.
It is not a de Polignac number, because 128032075648367 - 236 = 127963356171631 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (128032075648357) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 470746793 + ... + 471018690.
It is an arithmetic number, because the mean of its divisors is an integer number (9255671176752).
Almost surely, 2128032075648367 is an apocalyptic number.
128032075648367 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
128032075648367 is a deficient number, since it is larger than the sum of its proper divisors (20058663179665).
128032075648367 is a wasteful number, since it uses less digits than its factorization.
128032075648367 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 941766238.
The product of its (nonzero) digits is 81285120, while the sum is 62.
The spelling of 128032075648367 in words is "one hundred twenty-eight trillion, thirty-two billion, seventy-five million, six hundred forty-eight thousand, three hundred sixty-seven".
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