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128104113 = 342701371
BaseRepresentation
bin1111010001010…
…11011010110001
322221001100210210
413220223122301
5230243312423
620413414333
73113603244
oct750533261
9287040723
10128104113
1166347575
1236a9a3a9
1320703867
141302925b
15b3a6b93
hex7a2b6b1

128104113 has 4 divisors (see below), whose sum is σ = 170805488. Its totient is φ = 85402740.

The previous prime is 128104111. The next prime is 128104153. The reversal of 128104113 is 311401821.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 128104113 - 21 = 128104111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 128104113.

It is not an unprimeable number, because it can be changed into a prime (128104111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21350683 + ... + 21350688.

It is an arithmetic number, because the mean of its divisors is an integer number (42701372).

Almost surely, 2128104113 is an apocalyptic number.

It is an amenable number.

128104113 is a deficient number, since it is larger than the sum of its proper divisors (42701375).

128104113 is an equidigital number, since it uses as much as digits as its factorization.

128104113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42701374.

The product of its (nonzero) digits is 192, while the sum is 21.

The square root of 128104113 is about 11318.3087517526. The cubic root of 128104113 is about 504.1050226782.

Adding to 128104113 its reverse (311401821), we get a palindrome (439505934).

The spelling of 128104113 in words is "one hundred twenty-eight million, one hundred four thousand, one hundred thirteen".

Divisors: 1 3 42701371 128104113