Base | Representation |
---|---|
bin | 1011101010001100111000… |
… | …0101000011010100101111 |
3 | 1200101112201202001012021011 |
4 | 2322203032011003110233 |
5 | 3140014110244421340 |
6 | 43133132232250051 |
7 | 2462121424506262 |
oct | 272431605032457 |
9 | 50345652035234 |
10 | 12819639842095 |
11 | 40a2862535659 |
12 | 1530647540927 |
13 | 71cb6b5422a8 |
14 | 32468c476cd9 |
15 | 17370553a0ea |
hex | ba8ce14352f |
12819639842095 has 4 divisors (see below), whose sum is σ = 15383567810520. Its totient is φ = 10255711873672.
The previous prime is 12819639842077. The next prime is 12819639842101. The reversal of 12819639842095 is 59024893691821.
12819639842095 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12819639842095 - 233 = 12811049907503 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12819639842095.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1281963984205 + ... + 1281963984214.
It is an arithmetic number, because the mean of its divisors is an integer number (3845891952630).
Almost surely, 212819639842095 is an apocalyptic number.
12819639842095 is a deficient number, since it is larger than the sum of its proper divisors (2563927968425).
12819639842095 is an equidigital number, since it uses as much as digits as its factorization.
12819639842095 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2563927968424.
The product of its (nonzero) digits is 67184640, while the sum is 67.
The spelling of 12819639842095 in words is "twelve trillion, eight hundred nineteen billion, six hundred thirty-nine million, eight hundred forty-two thousand, ninety-five".
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