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12825398551437 = 321425044283493
BaseRepresentation
bin1011101010100010010101…
…0100110010001110001101
31200102002121002001221101100
42322220211110302032031
53140112404012121222
643135523505333313
72462414221645323
oct272504524621615
950362532057340
1012825398551437
1140a524814117a
121531794037239
13720578627904
14324a771d5d13
15173940dae4ac
hexbaa2553238d

12825398551437 has 6 divisors (see below), whose sum is σ = 18525575685422. Its totient is φ = 8550265700952.

The previous prime is 12825398551403. The next prime is 12825398551439. The reversal of 12825398551437 is 73415589352821.

12825398551437 is a `hidden beast` number, since 1 + 2 + 8 + 2 + 5 + 3 + 9 + 85 + 514 + 37 = 666.

It can be written as a sum of positive squares in only one way, i.e., 8461431593316 + 4363966958121 = 2908854^2 + 2089011^2 .

It is not a de Polignac number, because 12825398551437 - 228 = 12825130115981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12825398551439) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 712522141738 + ... + 712522141755.

Almost surely, 212825398551437 is an apocalyptic number.

It is an amenable number.

12825398551437 is a deficient number, since it is larger than the sum of its proper divisors (5700177133985).

12825398551437 is a wasteful number, since it uses less digits than its factorization.

12825398551437 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1425044283499 (or 1425044283496 counting only the distinct ones).

The product of its digits is 72576000, while the sum is 63.

The spelling of 12825398551437 in words is "twelve trillion, eight hundred twenty-five billion, three hundred ninety-eight million, five hundred fifty-one thousand, four hundred thirty-seven".

Divisors: 1 3 9 1425044283493 4275132850479 12825398551437