Base | Representation |
---|---|
bin | 10111111010100001… |
… | …10101100000001101 |
3 | 1020010202210221121120 |
4 | 23331100311200031 |
5 | 202243234434233 |
6 | 5521555551153 |
7 | 633106363224 |
oct | 137520654015 |
9 | 36122727546 |
10 | 12838983693 |
11 | 54992a9528 |
12 | 25a38bb4b9 |
13 | 1297c16793 |
14 | 89b213cbb |
15 | 5022484b3 |
hex | 2fd43580d |
12838983693 has 4 divisors (see below), whose sum is σ = 17118644928. Its totient is φ = 8559322460.
The previous prime is 12838983667. The next prime is 12838983737. The reversal of 12838983693 is 39638983821.
12838983693 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12838983693 - 218 = 12838721549 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12838983613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2139830613 + ... + 2139830618.
It is an arithmetic number, because the mean of its divisors is an integer number (4279661232).
Almost surely, 212838983693 is an apocalyptic number.
It is an amenable number.
12838983693 is a deficient number, since it is larger than the sum of its proper divisors (4279661235).
12838983693 is an equidigital number, since it uses as much as digits as its factorization.
12838983693 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4279661234.
The product of its digits is 13436928, while the sum is 60.
The spelling of 12838983693 in words is "twelve billion, eight hundred thirty-eight million, nine hundred eighty-three thousand, six hundred ninety-three".
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