Base | Representation |
---|---|
bin | 10010101101001010000… |
… | …000110010011100110101 |
3 | 11112212221022101110110120 |
4 | 102231022000302130311 |
5 | 132030033324122013 |
6 | 2422304354442153 |
7 | 161604216504621 |
oct | 22551200623465 |
9 | 4485838343416 |
10 | 1285436942133 |
11 | 456172708283 |
12 | 189162293359 |
13 | 942a6c55736 |
14 | 463033c4181 |
15 | 23685670123 |
hex | 12b4a032735 |
1285436942133 has 4 divisors (see below), whose sum is σ = 1713915922848. Its totient is φ = 856957961420.
The previous prime is 1285436942129. The next prime is 1285436942147. The reversal of 1285436942133 is 3312496345821.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1285436942133 - 22 = 1285436942129 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1285436942173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214239490353 + ... + 214239490358.
It is an arithmetic number, because the mean of its divisors is an integer number (428478980712).
Almost surely, 21285436942133 is an apocalyptic number.
It is an amenable number.
1285436942133 is a deficient number, since it is larger than the sum of its proper divisors (428478980715).
1285436942133 is an equidigital number, since it uses as much as digits as its factorization.
1285436942133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 428478980714.
The product of its digits is 3732480, while the sum is 51.
The spelling of 1285436942133 in words is "one trillion, two hundred eighty-five billion, four hundred thirty-six million, nine hundred forty-two thousand, one hundred thirty-three".
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