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12889141501265 = 52577828300253
BaseRepresentation
bin1011101110001111110010…
…1100110101110101010001
31200122012010102200022000222
42323203330230311311101
53142133430211020030
643225105002122425
72500131641042231
oct273437454656521
950565112608028
1012889141501265
11411a2883a38a7
1215420034b0415
13726596665ac3
14327ba2c09cc1
1517542200e3e5
hexbb8fcb35d51

12889141501265 has 4 divisors (see below), whose sum is σ = 15466969801524. Its totient is φ = 10311313201008.

The previous prime is 12889141501241. The next prime is 12889141501309. The reversal of 12889141501265 is 56210514198821.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3291463149121 + 9597678352144 = 1814239^2 + 3098012^2 .

It is a cyclic number.

It is not a de Polignac number, because 12889141501265 - 220 = 12889140452689 is a prime.

It is a super-2 number, since 2×128891415012652 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1288914150122 + ... + 1288914150131.

It is an arithmetic number, because the mean of its divisors is an integer number (3866742450381).

Almost surely, 212889141501265 is an apocalyptic number.

It is an amenable number.

12889141501265 is a deficient number, since it is larger than the sum of its proper divisors (2577828300259).

12889141501265 is an equidigital number, since it uses as much as digits as its factorization.

12889141501265 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2577828300258.

The product of its (nonzero) digits is 1382400, while the sum is 53.

The spelling of 12889141501265 in words is "twelve trillion, eight hundred eighty-nine billion, one hundred forty-one million, five hundred one thousand, two hundred sixty-five".

Divisors: 1 5 2577828300253 12889141501265