Base | Representation |
---|---|
bin | 1011101111110001010100… |
… | …1000111001101011010001 |
3 | 1200201200200221121120122220 |
4 | 2323330111020321223101 |
5 | 3143101034224022001 |
6 | 43245114450251253 |
7 | 2502046462553001 |
oct | 273742510715321 |
9 | 50650627546586 |
10 | 12915321314001 |
11 | 412a3a21a8677 |
12 | 15470aab86b29 |
13 | 728ba9446062 |
14 | 329167b4a001 |
15 | 175e55580c36 |
hex | bbf15239ad1 |
12915321314001 has 8 divisors (see below), whose sum is σ = 17220450195840. Its totient is φ = 8610203320752.
The previous prime is 12915321313967. The next prime is 12915321314023. The reversal of 12915321314001 is 10041312351921.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-12915321314001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12915321314081) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 638040 + ... + 5122278.
It is an arithmetic number, because the mean of its divisors is an integer number (2152556274480).
Almost surely, 212915321314001 is an apocalyptic number.
It is an amenable number.
12915321314001 is a deficient number, since it is larger than the sum of its proper divisors (4305128881839).
12915321314001 is an equidigital number, since it uses as much as digits as its factorization.
12915321314001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5444295.
The product of its (nonzero) digits is 6480, while the sum is 33.
Adding to 12915321314001 its reverse (10041312351921), we get a palindrome (22956633665922).
The spelling of 12915321314001 in words is "twelve trillion, nine hundred fifteen billion, three hundred twenty-one million, three hundred fourteen thousand, one".
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