Base | Representation |
---|---|
bin | 11101011110100011110011… |
… | …011110101011111101101111 |
3 | 122000000210012220100222010002 |
4 | 131132203303132223331233 |
5 | 113443034114202122401 |
6 | 1135421202345534515 |
7 | 36210265520602304 |
oct | 3536436336537557 |
9 | 560023186328102 |
10 | 129643377770351 |
11 | 383434a1a56815 |
12 | 12659908aa443b |
13 | 5745419a3aca3 |
14 | 2402ab70290ab |
15 | eec4c5e9ca6b |
hex | 75e8f37abf6f |
129643377770351 has 16 divisors (see below), whose sum is σ = 131170437684000. Its totient is φ = 128117898298368.
The previous prime is 129643377770213. The next prime is 129643377770371. The reversal of 129643377770351 is 153077773346921.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-129643377770351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (129643377770371) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1570460825 + ... + 1570543373.
It is an arithmetic number, because the mean of its divisors is an integer number (8198152355250).
Almost surely, 2129643377770351 is an apocalyptic number.
129643377770351 is a deficient number, since it is larger than the sum of its proper divisors (1527059913649).
129643377770351 is an equidigital number, since it uses as much as digits as its factorization.
129643377770351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91898.
The product of its (nonzero) digits is 140026320, while the sum is 65.
The spelling of 129643377770351 in words is "one hundred twenty-nine trillion, six hundred forty-three billion, three hundred seventy-seven million, seven hundred seventy thousand, three hundred fifty-one".
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